35r^2-2r-24=0

Solution for 35r^2-2r-24=0 equation:

35r^2-2r-24=0

a = 35; b = -2; c = -24;
Δ = b2-4ac
Δ = -22-4·35·(-24)
Δ = 3364
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3364}=58$
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-58}{2*35}=\frac{-56}{70}
=-4/5
$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+58}{2*35}=\frac{60}{70}
=6/7
$